X^2+y^2+2y=3

Solution for X^2+y^2+2y=3 equation:

X^2+X^2+2X=3

We move all terms to the left:

X^2+X^2+2X-(3)=0

We add all the numbers together, and all the variables

2X^2+2X-3=0

a = 2; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·2·(-3)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{7}}{2*2}=\frac{-2-2\sqrt{7}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{7}}{2*2}=\frac{-2+2\sqrt{7}}{4}
$